Create XML file

org.openrewrite.xml.CreateXmlFile

Create a new XML file.

Recipe source

GitHub, Issue Tracker, Maven Central

  • groupId: org.openrewrite

  • artifactId: rewrite-xml

  • version: 8.24.0

Options

TypeNameDescriptionExample

String

relativeFileName

File path of new file.

foo/bar/baz.xml

String

fileContents

Optional. Multiline text content for the file.

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <child>1</child></root>

Boolean

overwriteExisting

Optional. If there is an existing file, should it be overwritten.

Usage

This recipe has required configuration parameters. Recipes with required configuration parameters cannot be activated directly. To activate this recipe you must create a new recipe which fills in the required parameters. In your rewrite.yml create a new recipe with a unique name. For example: com.yourorg.CreateXmlFileExample. Here's how you can define and customize such a recipe within your rewrite.yml:

rewrite.yml
---
type: specs.openrewrite.org/v1beta/recipe
name: com.yourorg.CreateXmlFileExample
displayName: Create XML file example
recipeList:
  - org.openrewrite.xml.CreateXmlFile:
      relativeFileName: foo/bar/baz.xml
      fileContents: <?xml version="1.0" encoding="UTF-8"?>
<root>
    <child>1</child></root>

Now that com.yourorg.CreateXmlFileExample has been defined activate it in your build file:

  1. Add the following to your build.gradle file:

build.gradle
plugins {
    id("org.openrewrite.rewrite") version("6.12.0")
}

rewrite {
    activeRecipe("com.yourorg.CreateXmlFileExample")
}

repositories {
    mavenCentral()
}
  1. Run gradle rewriteRun to run the recipe.

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